Q2)
Let the 10V thingy be Vs. 10ohm resistor be r10, 9ohm resistor
be r9.
According to Kirchoff's current law, iunknown
=0A
First look at the loop on the right.
current through r10=1A(anticlockwise)
voltage drop across r10=Ri=10V
Next look at the loop on the left.
current through r9=1A (anticlockwise)
voltage drop across r9=Ri=9V
voltage across Is1=19V
therefore power across Is1=Vi=19W
